Thank you for reporting, we will resolve it shortly
Q.
In a hydrogen atom, if the energy of electron in the ground state is $- x\, eV$, then that in the $2^{\text {nd }}$ excited state of $He ^{+}$is
Structure of Atom
Solution:
$E _{ n }=\frac{ E _{\text {ground state }}}{ n ^{2}} \times z ^{2}$
$=-\frac{x}{(3)^{2}} \times(2)^{2}=-\frac{4}{9} \times eV$
$E_{\text {ground }}=x eV$ given
$n=3$ because $2^{\text {nd }} $ excited state
$z=2$ because