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Chemistry
In a hydrogen atom, if energy of an electron in ground state is -13.6 eV, then that in the 2nd excited state is:
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Q. In a hydrogen atom, if energy of an electron in ground state is $-13.6\, eV$, then that in the $2^{nd}$ excited state is:
Structure of Atom
A
$-1.51 \,eV$
27%
B
$-3.4 \,eV$
47%
C
$-6.04 \,eV$
9%
D
$-13.6 \,eV$
17%
Solution:
2nd excited state means third energy level.
$E_{3} =\frac{E_{1}}{3^{2}} =\frac{13.6}{9} =-1.51 eV $