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Q. In a hydrogen atom, if energy of an electron in ground state is $-13.6\, eV$, then that in the $2^{nd}$ excited state is:

Structure of Atom

Solution:

2nd excited state means third energy level.
$E_{3} =\frac{E_{1}}{3^{2}} =\frac{13.6}{9} =-1.51 eV $