Q. In a hydrogen atom, find the binding energy of an electron at $n=4$ state:
NTA AbhyasNTA Abhyas 2020
Solution:
answer
Binding energy is nothing but the energy required to remove an electron from its orbit which is given by the equation
$E_{n}=\frac{13 . 6}{n^{2}}eV$
$\Rightarrow E_{4}=\frac{13 . 6}{\left(4\right)^{2}}$
$\Rightarrow E_{4}=0.85eV$
Binding energy is nothing but the energy required to remove an electron from its orbit which is given by the equation
$E_{n}=\frac{13 . 6}{n^{2}}eV$
$\Rightarrow E_{4}=\frac{13 . 6}{\left(4\right)^{2}}$
$\Rightarrow E_{4}=0.85eV$