Thank you for reporting, we will resolve it shortly
Q.
In a hydrogen atom, a Bohr's orbit has diameter of about $4.232\, \mathring{A}$. What is the maximum number of electrons that can be accommodated in this shell?
Structure of Atom
Solution:
Diameter $=4.232\,\mathring{A}$
$\therefore $ Radius $=2.116\,\mathring{A}$
Now, $r _{ n }=0.529 \times n ^{2} \,\mathring{A}$ [for H-atom]
$\therefore 2.116=0.529 \times n^{2} \,\mathring{A}$
$\therefore n ^{2}=4$
$\therefore n =2$
$\therefore $ Maximum number of $e ^{-}$in the second shell
$=2 n^{2}=2 \times(2)^{2}=8$