Question

In a hotel, four rooms are available. Six persons are to be accommodated in these four rooms in such a way that each of these rooms contains at least one person and at most two persons. Then the number of all possible ways in which this can be done is ______

Answer 1

Two rooms accommodate two persons each other two room have one person each.
Total ways $\frac{6 !}{(2 !)^{2}(1 !)^{2} 2 ! 2 !} \times 4 !=1080$