1. Tardigrade
  2. Question
  3. Chemistry
  4. In a half reaction, nitrate is reduced by 6e- reduction to x as follows 7H++NO3 -+6e- arrow 2H2O+x . The 'x' in the reaction is

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Q. In a half reaction, nitrate is reduced by $6e^{-}$ reduction to $x$ as follows $7H^{+}+NO_{3}^{ -}+6e^{-} \rightarrow 2H_{2}O+x$ . The $'x'$ in the reaction is

NTA AbhyasNTA Abhyas 2022

Solution:

$\overset{+ 5}{N}O_{3}^{ -} \rightarrow \overset{- 1}{N}H_{2}OH$ ,
Change in oxidation number is $6$