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  4. In a ground, a cyclist follows a track that turn to his right by an angle of 60° after every 100 m. The displacement of the cyclist from the starting point to the fourth turn:

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Q. In a ground, a cyclist follows a track that turn to his right by an angle of $60^{\circ}$ after every $100 m$. The displacement of the cyclist from the starting point to the fourth turn:

Motion in a Plane

Solution:

Cyclist starts from A and reaches a point $E$
image
So their displacement is $AE$ $AE =\sqrt{ AF ^{2}+ FE ^{2}}$
(According to pythagoras theorem)
$A E=\sqrt{(100)^{2}+(100)^{2}}$
$AE =100 \sqrt{2}$