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Q. In a given common Emitter transistor, Emitter current is changed by $2.1mA$ . This results in a change of $2mA$ in the collector current and a change of $0.05V$ in the Emitter-base voltage. The input resistance (in ohm) is :-

NTA AbhyasNTA Abhyas 2022

Solution:

$ΔI_{E}=ΔI_{B}+ΔI_{C}$
$2.1=ΔI_{B}+2\Rightarrow ΔI_{B}=0.1mA$
$v_{\text{in }}=ΔI_{B}R_{\text{in }}$
$0.05=10^{- 4}R_{in}$
$R_{\text{in }}=500\Omega$