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Q.
In a flight $50$ people speak Hindi, $20$ speak English and $10$ speak both English and Hindi. The number of people who speak at least one of the two languages is
Let $H=$ People who speak Hindi
$E=$ People who speak English
According to the questions,
$n(H)=50, n(E)=20, n(H \cap E)=10$
$\therefore $ Number of people who speak atleast two language $ =n(H \cup E) $
$=n(H)+n(E)-n(H \cap E) $
$=50+20-10=60$