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Q. In a first order reaction the reacting substance has half-life period of ten minutes. What fraction of the substance will be left after an hour the reaction has occurred?

Chemical Kinetics

Solution:

$t_{1/2}=10$ No. of half-life $=\frac{60}{10}= 6$ half-life
$C_{t}=\frac{C_{0}}{\left(2\right)^{n}}=\frac{C_{0}}{\left(2\right)^{6}}=\left(\frac{C_{0}}{64}\right)$