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  4. In a face centred cubic lattice, atoms of A form the comer points and atoms of B form the face centred points. If two atoms of A are missing from the comer points, the formula of the ionic compound is :

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Q. In a face centred cubic lattice, atoms of $A$ form the comer points and atoms of $B$ form the face centred points. If two atoms of $A$ are missing from the comer points, the formula of the ionic compound is :

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Solution:

A form comer points and two atoms of $A$ are missing from comer
$\therefore $ Atoms at comer $\left(A\right)=6\times\frac{1}{8}=\frac{3}{4}$
Atoms at face centre $\left(B\right)=6\times \frac{1}{2}=3$
$\therefore A_{3/4}B_{3}i.e., AB_{4}$