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Q. In a diffraction pattern due to a single slit of width 'a', the first minimum is observed at an angle $30^{\circ}$ when light of wavelength $5000 \mathring A $ is incident on the slit. The first secondary maximum is observed at an angle of :

NEETNEET 2016Wave Optics

Solution:

For first minima , $\sin 30^{\circ} = \frac{\lambda}{a} = \frac{1}{2}$
First secondary maxima will be at
$ \sin \theta = \frac{3 \lambda}{2a} = \frac{3}{2} \left( \frac{1}{2} \right) \, \Rightarrow \, \theta = \sin^{-1} \left( \frac{3}{4} \right)$