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Q. In a crystal of an ionic compound, the ions B form the close packed lattice and the ions A occupy all the tetrahedral voids. The formula of the compound is

The Solid State

Solution:

The number of tetrahedral voids is two per atom of the crystal in a close packed structure. Since tetrahedral voids are occupied by $A$ ions, there are two $A$ ions per $B$ ion in the crystal. The formula of the compound is $A_2B$.