1. Tardigrade
  2. Question
  3. Chemistry
  4. In a container equilibrium N2O4 (g) leftharpoons 2NO2 (g) is attained at 25°C. The total equilibrium pressure in container is 380 torr. If equilibrium constant of above equilibrium is 0.667 atm, then degree of dissociation of N2O4 at this temperature will be:

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Q. In a container equilibrium $N_{2}O_{4} (g) \rightleftharpoons 2NO_{2} (g)$ is attained at $25°C.$ The total equilibrium pressure in container is $380$ torr. If equilibrium constant of above equilibrium is $0.667$ atm, then degree of dissociation of $N_{2}O_{4}$ at this temperature will be:

Equilibrium

Solution:

$K_{p}=0.667 \,\,atm =\frac{2}{3} \,\, atm= \frac{4\alpha^{2}}{1-\alpha^{2}}; P=\frac{4\alpha^{2}}{1-\alpha^{2}}. \frac{1}{2}$
$SO, \frac{4\alpha^{2}}{1-\alpha^{2}} =\frac{4}{3} \Rightarrow 3\alpha^{2}=1\alpha^{2}$
$So, \alpha^{2} =\frac{1}{4}\Rightarrow \alpha=\frac{1}{2}$