1. Tardigrade
  2. Question
  3. Chemistry
  4. In a conductivity cell, the two platinum electrodes, each of area 10 cm 2, are fixed 1.5 cm apart. The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 ohms, find the equivalent conductance of the salt solution is

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Q. In a conductivity cell, the two platinum electrodes, each of area $10\, cm ^{2}$, are fixed $1.5\, cm$ apart. The cell contained $0.05\, N$ solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of $50$ ohms, find the equivalent conductance of the salt solution is

Electrochemistry

Solution:

$\Lambda_{ eq } =\frac{1000}{ c } \times \frac{l}{ a } \times G$

$=\frac{1000 \times 10^{-6} m ^{3}\, L ^{-1}}{0.05\, eq\, L ^{-1}} \times \frac{1.5 \times 10^{-2} m }{5.0 \times 10^{-4} m ^{2}} \times \frac{1}{50\, ohm }$

$=0.012\, S\, m ^{2}\, eq ^{-1} $