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Q. In a compound C, H and N atoms are present in 9 : 1 : 3.5 weight. Molecular weight of compound is 108. Molecular formula of the compound is

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$\begin{matrix}C&&H&&N\\ 9&:&1&:&3.5\\ \frac{9}{12}&:&\frac{1}{1}&:&\frac{3.5}{14}\\ \frac{3}{4}&:&\frac{1}{1}&:&\frac{1}{4}\\ 3&:&4&:&1\end{matrix}$
Empirical formula $= C_{3}H_{4}N$
$\left(C_{3}H_{4}N\right)_{n} = 108$
$\left(12 × 3 + 1 × 4 + 14\right)_{n} = 108$
$54n = 108 ⇒ n = 108/54 = 2$
Molecular formula $= C_{6}H_{8}N_{2}$