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Q. In a collection of 6 mathematics books and 4 physics books, the probability that 3 particular mathematics books will be together is:

Probability

Solution:

Total ways in a collection of books
= (6 + 4)! =10!
Let 3 books of maths consider as one book, then (3 maths + 3 maths + 4 physics) = 6 books
$\therefore $ Favourable cases = 3! × 8!
$\therefore $ Required probability
$ = \frac{3 ! \times 8!}{10!} = \frac{3.2.1.8!}{10.9.8!} = \frac{1}{15}$