1. Tardigrade
  2. Question
  3. Chemistry
  4. In a closed packed structure of mixed oxides, it is found that lattice has O2- (oxide ion) and half of octahedral voids are occupied by trivalent cations (A3+) and one-eighth of tetrahedral voids are occupied by divalent cations (B2+). Thus, mixed oxide is

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Q. In a closed packed structure of mixed oxides, it is found that lattice has $O^{2-}$ (oxide ion) and half of octahedral voids are occupied by trivalent cations $(A^{3+})$ and one-eighth of tetrahedral voids are occupied by divalent cations $(B^{2+})$. Thus, mixed oxide is

The Solid State

Solution:

In closed packed structure lattice.
Number of octahedral voids $= 1$
Number of tetrahedral voids $= 2$
image
Charge on $(A_2B )^{x+} = (2 \times 3 + 2 \times 1) = + 8$
Thus, number of $O$-atoms $= \frac{8}{2} = 4$ (to balance charge)
Lattice is $A_2BO_4$.