Thank you for reporting, we will resolve it shortly
Q.
In a closed organ pipe of length $105 \,cm$, standing waves are set up corresponding to third overtone. What distance from the closed end, a pressure node is formed?
Waves
Solution:
In a closed pipe $f=\frac{(2 P+1)}{4 l} v$
For third overtone $(f)=\frac{7 v}{4 l}$
$\lambda=\frac{v}{f}=\frac{v}{7 v} \times 4 l $
$\lambda=\frac{4 l}{7}$
$\lambda=\frac{4 \times 105}{7} $
$\lambda=60 \,cm$
First pressure node will be formed $\frac{\lambda}{4}$
