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  4. In a class of 60 students, 25 students play cricket and 20 students play tennis and 10 students play both the games. Then the number of students who play neither is

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Q. In a class of $60$ students, $25$ students play cricket and $20 $ students play tennis and $10$ students play both the games. Then the number of students who play neither is

Solution:

$n(U)=60$
$n(C)=25$
$n(T)=20$
$n(C \cap T)=10$
$n\left(C^{C} \cap T^{C}\right)=n\left((C \cup T)^{C}\right)$
$=n(U)-n(C \cup T)$
$=60-[25+20-10]$
$=25$