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Q. In a circuit, $5$ percent of total current passes through a galvanometer. If resistance of the galvanometer is $G$. Then the value of the shunt is

Bihar CECEBihar CECE 2011Current Electricity

Solution:

$\frac{S}{G}=\frac{5}{95}=\frac{1}{19}$
$S=\frac{G}{19}$

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