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Q.
In a circle of diameter $40 \,cm$, the length of a chord is $20\, cm$, then the length of minor arc of the chord is
Trigonometric Functions
Solution:
Since, diameter of the circle $=40 \,cm$
$\therefore $ Radius of the circle $(r)=20 \,cm$
and length of the chord $(l)=20 \,cm$
From the shown figure, it is clear that $\angle A O B=60^{\circ}=\frac{\pi}{3}$ radian
$\therefore$ Length of minor arc of the chord $(l)=$ radius of circle $(r) \times$ angle subtended in radian by the minor arc $(\theta)$
$=20 \times \frac{\pi}{3}=\frac{20 \pi}{3} cm$
