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Q. In a certain gaseous reaction between $A$ and $B , A +3 B \rightarrow AB _3$. The initial rates are reported as follows:
[A] [B] Rate
$0.1\,M$ $0.1\,M$ $0.002\,Ms^{-1}$
$0.2\,M$ $0.1\,M$ $0.002\,Ms^{-1}$
$0.3\,M$ $0.2\,M$ $0.008\,Ms^{-1}$
$0.4\,M$ $0.3\,M$ $0.018\,Ms^{-1}$

The rate law is

Chemical Kinetics

Solution:

In experiment I and II, $[ B ]$ is constant and $[ A ]$ is doubled. The rate does not change. So order w.r.t $[ A ]=$ zero
Let rate $=k[ A ]^0[ B ]^x$
$r_2=0.002 \,M s ^{-1}=k[0.1]^x$
$r_3=0.008 \,M s ^{-1}=k[0.2]^x$
$\frac{r_3}{r_2}=4=(2)^x $
$\therefore(2)^2=(2)^x$
$x=2$
So order w.r.t. $[ B ]=2$
Rate $=k[ A ]^0[ B ]^2$