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  4. In a capacitor of capacitance 20 μ F the distance between the plates is 2 mm. If a dielectric slab of width 2 mm and dielectric constant 2 is inserted between the plates, then the new capacitance will be:

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Q. In a capacitor of capacitance $20\, \mu F$ the distance between the plates is $2\, mm$. If a dielectric slab of width $2 \,mm$ and dielectric constant $2$ is inserted between the plates, then the new capacitance will be:

Electrostatic Potential and Capacitance

Solution:

Full space between plates is filled with dielectric
$\Rightarrow C^{\prime}=2\, C$
$\Rightarrow C^{\prime}=40\, \mu F$