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  4. In a building there are 15 bulbs of 45 W, 15 bulbs of 100 W, 15 small fans of 10 W and 2 heaters of 1 kW. The voltage of electric main is 220 V. The minimum fuse capacity (rated value) of the building will be:

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Q. In a building there are $15$ bulbs of $45\, W, 15$ bulbs of $100\, W$, $15$ small fans of $10\, W$ and $2$ heaters of $1\, kW$. The voltage of electric main is $220\, V$. The minimum fuse capacity (rated value) of the building will be:

JEE MainJEE Main 2020Current Electricity

Solution:

$220 \,I = P = 15 × 45 + 15 × 100 + 15 × 10 + 2 × 10^{3}$
$I = \frac{4325}{220} = 19.66$
$I \simeq 20\,A$