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Q.
In a Bohr's model of an atom, when an electron jumps from n = 1 to n = 3, how much energy will be absorbed?
NTA AbhyasNTA Abhyas 2022
Solution:
Energy of an atom when $n=1$
$
E _{1}=-\frac{1312}{(1)^{2}}=-1312 kJ mol ^{-1}
$
Similarly energy when $n =3,\left( E _{3}\right)=-\frac{1312}{(3)^{2}}$
$
=-145.7 kJ mol ^{-1}
$
The energy absorbed when an electron jumps from $n=1$ to $n=3$
$E_{3}-E_{1}=-145.7-\left(- 1312\right)=1166.3\text{ kJ mo}\left(\text{l}\right)^{- 1}$
$=\frac{1166.3}{6.023 \times 1 0^{23}}=193.6\times 10^{- 23}kJ$
$=193.6\times 10^{- 20}J\left[\text{1 Joule} = 1 0^{7} \text{ ergs}\right]$
$193.6\times 10^{- 13}ergs=0.1936\times 10^{- 10}ergs$