1. Tardigrade
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  3. Chemistry
  4. In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking Kf for water as 1.85, the freezing point of the solution will be nearest to

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Q. In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking $K_f$ for water as 1.85, the freezing point of the solution will be nearest to

Solutions

Solution:

$HX \rightleftharpoons H ^{+}+ X ^{-}$
$i=\frac{1-0.3+0.3+0.3}{1}=1.3$
$\Delta T_f=i K_f m$
$=1.3 \times 1.85 \times 0.2=0.48$
$\therefore T_f=(0-0.48)^{\circ} C =0-48^{\circ} C$.