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Physics
In 88 Ra 226 nucleus, there are:
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Q. $In _{88} Ra ^{226}$ nucleus, there are:
Nuclei
A
138 protons and 88 neutrons
26%
B
138 neutrons and 88 protons
47%
C
226 protons and 88 electrons
26%
D
226 neutrons and 138 electrons
0%
Solution:
${ }_{z} X ^{A}={ }_{88} Ra ^{226}$
Number of protons $Z=88$
Number of neutrons
$= A = Z =226-88=138$