Question

Consider the above reaction where $6.1\,g$ of benzoic acid is used to get $7.8\,g$ of $m$ -bromo benzoic acid. The percentage yield of the product is ____.
(Round off to the Nearest integer)
[Given : Atomic masses : $C =12.0 u , H : 1.0 u, O : 16.0 u , Br =80.0 u ]$

Answer 1

Moles of Benzoic acid $=\frac{6.1}{122}$

= moles of $m$ -bromobenzoic acid

So, weight of $m$ -bromobenzoic acid

$=\frac{6.1}{122} \times 201 gm$

$=10.05\,gm$

$\%$ yield $=\frac{\text { Actual weight }}{\text { Theoretical weight }} \times 100$

$=\frac{7.8}{10.05} \times 100$

$=77.61 \%$