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Q.
Illumination of the sun at noon is maximum because :
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Solution:
The intensity of illumination is given by $ I=\frac{P\cos \theta }{{{r}^{2}}} $ .....(i) where P = power of the source r = distance between source and point $ \theta $ = angle of incidence when $ \theta =0, $ I will be maximum. Hence the rays from the sun .are incident normally on the earth surface.