1. Tardigrade
  2. Question
  3. Chemistry
  4. If Zn2+/Zn electrode is diluted 100 times, then the charge in reduction potential is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $Zn^{2+}/Zn$ electrode is diluted 100 times, then the charge in reduction potential is

Electrochemistry

Solution:

$E_{Zn^{+}/ Zn}= E^{0} _{Zn^{2+}/ Zn} -\frac{0.059}{2} log \frac{1}{\left|Zn^{2+}\right|}$
$E_{Zn^{+} /Zn}= E^{0} _{Zn^{2+} /Zn} + 0.0295\, log\, C $
When solution is diluted $100$ times
$E '_{Zn^{2+}/Zn} = E ° _{Zn^{2+}/Zn} + 0.0295\, log \frac{C}{100}$
$= E°_{Zn^{2+}/Zn}+0.0295 \,log\, C - 0.0295 \times 2$
$= E_{Zn^{2+}/Zn} -0.059$
$E'_{Zn^{2+}/Zn} - E_{Zn^{2+}/Zn} = -0.059 \,V $
$= - 59 \,mV$
Thus $R.P$. will decrease by $59 \,mV$.