Question

If $y=\tan x \tan 2 x \tan 3 x$ then $\frac{d y}{d x}$ is equal to-

• A. $3 \sec ^2 3 x \tan x \tan 2 x +\sec ^2 x \tan 2 x \tan 3 x +2 \sec ^2 2 x \tan 3 x \tan x$
• B. $2 y(\text{cosec} 2 x+2 \text{cosec} 4 x+3 \text{cosec} 6 x)$
• C. $3 \sec ^2 3 x-2 \sec ^2 2 x-\sec ^2 x$
• D. $\sec ^2 x+2 \sec ^2 2 x+3 \sec ^2 3 x$

Answer 1

Answer: (A), (B), (C)

Correct answer is (a) $3 \sec ^2 3 x \tan x \tan 2 x +\sec ^2 x \tan 2 x \tan 3 x +2 \sec ^2 2 x \tan 3 x \tan x$Correct answer is (b) $2 y(\text{cosec} 2 x+2 \text{cosec} 4 x+3 \text{cosec} 6 x)$Correct answer is (c) $3 \sec ^2 3 x-2 \sec ^2 2 x-\sec ^2 x$