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  4. If y = log( sec x + tan x), then (dy/dx) =

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Q. If $y = \log(\sec x + \tan x),$ then $\frac{dy}{dx} = $

Limits and Derivatives

Solution:

$\frac{dy}{dx} = \frac{1}{\sec x + \tan x} . \left(\sec x \tan x + \sec^{2} x\right)$
$ = \frac{\sec x\left[\tan x +\sec x\right]}{\sec x +\tan x} = \sec x$