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Q. If $ y={{\log }_{a}}x,x>0, $ then, $ \frac{dy}{dx} $ is equal to:

KEAMKEAM 2006

Solution:

$ y={{\log }_{a}}x, $ $ x>0 $ $ \Rightarrow $ $ y=\frac{\log x}{\log a},x>0 $ $ \Rightarrow $ $ \frac{dy}{dx}=\frac{1}{x\log a},x>0 $ $ =\frac{1}{x}{{\log }_{a}}e $