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Q. If y=4x5 is tangent to the curve y2=px3+q at (2,3) then (p,q) is

NTA AbhyasNTA Abhyas 2020Application of Derivatives

Solution:

Curve is y2=px3+q
2ydydx=3px2
(dydx)(2,3)=3p.42.3
4=2p
p=2
Also, curve is passing through (2,3)
9=8p+q
q=7
(p,q) is (2,7)