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Q. If $y^3+x^3+3 x y=15$, then $\frac{d y}{d x}$ at $(1,2)$ is equal to

Continuity and Differentiability

Solution:

$3 y^2 y^{\prime}+3 x^2+3\left(x y^{\prime}+y\right)=0 \Rightarrow 4 y^{\prime}+1+1 y^{\prime}+2=0 \Rightarrow y^{\prime}=\frac{-3}{5}$