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Q. If $y=2^{Log\,x}$, then $\frac {dy}{dx}$ is

KCETKCET 2007Continuity and Differentiability

Solution:

Given, $y = 2^{\log x} $
$ \Rightarrow \frac{dy}{dx} = 2^{\log x} . \log_{e} 2. \frac{1}{x} $
$ \left[\because \frac{d}{dx} \left(a^{x} \right) = a^{x} \log_{e} a\right] $
$ \Rightarrow \frac{dy}{dx} = \frac{2^{\log x} . \log_{e}2}{x} $