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Q. If $x+iy=\frac{a+ib}{a-ib}$, then $x^{2}+y^{2}=$

Complex Numbers and Quadratic Equations

Solution:

We have, $x+ iy=\frac{a+ib}{a-ib}$
Taking modulus both sides, we get
$\sqrt{x^{2}+y^{2}}=1$
$\Rightarrow \,x^{2}+y^{2}=1$