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Q. If $x \,g$ of $A$ (atomic mass 50 ) contains $n$ atoms, how many atoms are there in $20 x$ g of elements B: (at wt. 100)

Some Basic Concepts of Chemistry

Solution:

For $A$

$50 \,g\, A$ would contain atoms $= N _{ A }$

$x \,g$ A would contain atoms $=\frac{ N _{ A }}{50} \times x g = n$ atoms

For $B$

$100 \,g\, B$ would contains atoms $= N _{ A }$

$20 \,xg \,B$ would contains atoms $=\frac{ N _{ A }}{100} \times 20 xg =\frac{ N _{ A }}{5} x$

$\frac{ N _{ A }}{50} x$ corresponds to atoms $= n$

$ \frac{ N _{ A }}{5} x$ corresponds to atoms $=\frac{ n }{\frac{ N _{ A } x}{50}} \times \frac{ N _{ A }}{5} x$

$=\frac{ n \times 50}{ N _{ A } x} \times \frac{ N _{ A }}{5} x $

$=10 \,n$