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Q. If x=n=0an,y=n=0bn,z=n=0cn where a,b,c are in A.P and |a|<1,|b|<1,|c|<1 then x,y,z are in

Sequences and Series

Solution:

x=n=0an=11a
a=11x
y=n=0bn=11bb=11y
z=n=0cn=11cc=11z
a,b,c are in A.P.
OR 2b=a+c
2(11y)=11x+11y2y=1x+1z
x,y,z are in H.P