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Q.
If x denotes displacement in time t and x = a cos t, then acceleration is given by
Application of Derivatives
Solution:
Given displacement x = a cos t
$\therefore $ velocity $= v = \frac{dx}{dt} = a. - \sin \, t = - a \, \sin \, t$
$\Rightarrow \, v = - a \, \sin \, t$
$\because $ acceleration $a = \frac{dv}{dt} = - a \, \cos \, t $