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  4. If x and y satisfy the relation (x-1)2+y2=1, then the possible value of (x+y) is equal to

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Q. If $x$ and $y$ satisfy the relation $(x-1)^2+y^2=1$, then the possible value of $(x+y)$ is equal to

Complex Numbers and Quadratic Equations

Solution:

$\text { Let } x=1+\cos \theta \text { and } y=\sin \theta $
$\therefore x+y=1+\cos \theta+\sin \theta$
$\text { Hence } 1-\sqrt{2} \leq x+y \leq 1+\sqrt{2} $