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  4. If |x -1| ≤ 1, then

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Q. If $|x -1| \leq 1$, then

KCETKCET 2017Linear Inequalities

Solution:

We have.
$|x-2| \leq 1$
$\Rightarrow -1 \leq x-2 \leq 1$
$\Rightarrow -1+2 \leq x-2+2 \leq 1+2$
$\Rightarrow 1 \leq x \leq 3$
$ \therefore x \in[1,3]$
Note Correction in the question
$|x-2| \leq 1$