Question

If $ X=\left\{-2, -1, 0, 1,2,3, 4, 5, 6, 7, 8\right\} $ and $ A=\left\{x : \left|x-2\right|\le3, x \, is\,an\, integer\right\}, $ then $ X-A= $

• A. $ \{-2, 6, 7, 8\} $
• B. $ \{-2, -1, 1, 2, 3, 4, 5, 6\} $
• C. $ \{-1, 0,1,2,3, 4, 5, 7, 8\} $
• D. $\{-2, -1, 2, 3, 6, 7, 8\} $

Answer 1

Answer: (A)

We have, $X = {-2, - 1 , 0 , 1 , 8 }$ and
$A = {x : | x - 2| \le 3, x \text{ is an integer}}$
$\therefore A = {-1, 0, 1, 2, 3, 4, 5}$
Now, $X - A = {-2, 6, 7, 8}$