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  4. If we add dilute aqueous solution of KI dropwise to AgNO 3 aqueous solution, the AgI colloid formed will have

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Q. If we add dilute aqueous solution of $KI$ dropwise to $AgNO _{3}$ aqueous solution, the $AgI$ colloid formed will have

Surface Chemistry

Solution:

$AgNO _{3(a q)}+ KI _{(a q)} \rightarrow \underset{\text{colloide}}{[ AgI]} I ^{-}+ KNO _{3}$

AgI will absorb $I^{-}$ from KI electrolyte to form $[AgI]I^{-}$ Therefore, it is negatively charged.