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Physics
If wavelength λ =5400 mathringA is threshold value for a certain metal, then its work function would be:
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Q. If wavelength $ \lambda =5400\,\mathring{A}$ is threshold value for a certain metal, then its work function would be:
Rajasthan PMT
Rajasthan PMT 2006
Dual Nature of Radiation and Matter
A
2.3 eV
56%
B
0.025 eV
24%
C
10 eV
15%
D
0.23 eV
6%
Solution:
$ E=\frac{h c}{\lambda} J =\frac{. h c}{\lambda \times 1.6 \times 10^{-19}} eV$
$\Rightarrow E=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{5400 \times 10^{-10} \times 1.6 \times 10^{-19}} eV $
$ \Rightarrow E=2.3 \,eV$