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Q.
If wavelength is equal to the distance travelled by the electron in one second, then
Structure of Atom
Solution:
$\lambda=\frac{h}{m v}$ distance travelled in one second by velocity $V=v cm =\lambda$
$\lambda=\frac{h}{m \lambda} \Rightarrow \lambda^2=\frac{h}{m}$
$ \Rightarrow \lambda=\sqrt{\frac{h}{m}}$