1. Tardigrade
  2. Question
  3. Physics
  4. If vecP ⋅ vecQ=P Q, then angle between vecP and vecQ is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If $\vec{P} \cdot \vec{Q}=P Q$, then angle between $\vec{P}$ and $\vec{Q}$ is

Motion in a Plane

Solution:

$\cos \theta=\frac{\vec{P} \cdot \vec{Q}}{P Q}=1 $
$\therefore \theta=0^{\circ}$