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Q. If $\vec{a}$ and $\vec{b}$ are two non-zero vectors such that $| \vec{a} . \vec{b}| = | \vec{a} \times \vec{b}|$ , then the angle between $\vec{a}$ and $\vec{b}$ is

COMEDKCOMEDK 2005Vector Algebra

Solution:

$\left|\vec{a}.\vec{b}\right|=\left|\vec{a} \times \vec{b}\right| $
$\Rightarrow \left| \left|\vec{a}\right|\left|\vec{b}\right|\cos \theta \right|=\left|\left|\vec{a}\right|\left|\vec{b}\right|\sin \theta \hat{n} \right|$
$\Rightarrow \left|\vec{a}\right|\left|\vec{b}\right|\left|\cos \theta \right| =\left| \left|\vec{a}\right| \left|\vec{b}\right|\sin\theta \hat{n} \right|$
$\Rightarrow \left|\cos \theta\right| = \left|\sin \theta\right|$
$\Rightarrow \theta= \frac{\pi}{4} $ and $\frac{3\pi}{4} $ are possible values