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Chemistry
If V is the volume of one molecule of gas under given conditions, the van der Waal’s constant b is
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Q. If $V$ is the volume of one molecule of gas under given conditions, the van der Waal’s constant $b$ is
BITSAT
BITSAT 2018
A
4V
22%
B
$\frac{4V}{N_0}$
17%
C
$\frac{N_0}{4V}$
12%
D
$4VN_0$
49%
Solution:
van der Waals’s constant $b = 4$ times
the actual volume of $1$ mole molecules = $4 \,VN_0$